0.255=2x-2x^2

Solution for 0.255=2x-2x^2 equation:

0.255=2x-2x^2

We move all terms to the left:

0.255-(2x-2x^2)=0

We get rid of parentheses

2x^2-2x+0.255=0

a = 2; b = -2; c = +0.255;
Δ = b2-4ac
Δ = -22-4·2·0.255
Δ = 1.96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-\sqrt{1.96}}{2*2}=\frac{2-\sqrt{1.96}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+\sqrt{1.96}}{2*2}=\frac{2+\sqrt{1.96}}{4}
$